考研851 自动控制原理
真题 · 真题解析 · p.2
\[ \frac{U_0(s)}{U_i(s)} = \frac{R_2}{R_1/\dfrac{1}{Cs}+R_2} = \frac{R_2}{\dfrac{R_1\cdot\dfrac{1}{Cs}}{R_1+\dfrac{1}{Cs}}+R_2} = \frac{R_2}{\dfrac{R_1}{R_1Cs+1}+R_2} = \frac{R_1R_2Cs+R_2}{R_1R_2Cs+R_1+R_2} \]

四、(1)系统的闭环传递函数为:

\[ \frac{x_0(s)}{x_i(s)} = \frac{\dfrac{k_1k_2}{s(T_1s+1)(T_2s+1)}+\dfrac{k_2\cdot G_0(s)}{s(T_2s+1)}}{1+\dfrac{k_1k_2}{s(T_1s+1)(T_2s+1)}} = \frac{k_2G_0(s)\cdot(T_1s+1)+k_1k_2}{s(T_1s+1)(T_2s+1)+k_1k_2} \]

\(\therefore\) 系统的特征方程 \(D(s)=s(T_1s+1)(T_2s+1)+k_1k_2 = T_1T_2s^3+(T_1+T_2)s^2+s+k_1k_2\)

\(\therefore\) Routh表为:

\(s^3\) \(T_1T_2\) \(1\)
\(s^2\) \(T_1+T_2\) \(k_1k_2\)
\(s^1\) \(\dfrac{T_1+T_2-k_1k_2T_1T_2}{T_1+T_2}\)
\(s^0\) \(k_1k_2\)

\(\therefore\) 第一列均大于0时,系统才稳定,即:

\[ \begin{cases} T_1T_2>0 \\ T_1+T_2>0 \\ \dfrac{T_1+T_2-k_1k_2T_1}{T_1+T_2}>0 \\ k_1k_2>0 \end{cases} \]

\(\therefore\) 综上:

\[ \begin{cases} 0<k_1k_2<\dfrac{T_1+T_2}{T_1T_2} \\ T_1T_2>0 \end{cases} \]

(2)\(\because X_2(t)=V_0t\)(为非零常数)